we calculate by $CuSO _4( s ) \rightleftharpoons Cu ^{2+}+ SO _4{ }^{2-}$
Solubility product for above equilibrium is $K _{ sp }=\left[ Cu ^{2+}\right]\left[ SO _4{ }^{2-}\right]$ where $\left[ Cu ^{2+}\right]$ and $\left[ SO _4{ }^{2-}\right]$ are concentrations of ions which are dissociated from $CuSO _4$.
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[Atomic masses $\mathrm{Cu}: 63.54\, \mathrm{u}, \mathrm{S}: 32\, \mathrm{u}, \mathrm{O}: 16 \,\mathrm{u}, \mathrm{H}: 1\, \mathrm{u}]$
