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6.2. Equilibrium - II (icon Equilibrium) — Chemistry STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceChemistry6.2. Equilibrium - II (icon Equilibrium)1 Mark
MCQ
In a saturated solution of the sparingly soluble strong electrolyte $AgIO_3$ (molecular mass $= 283$) the equilibrium which sets in is

$AgIO_{3(s)} \rightleftharpoons  Ag^+_{(aq)} +IO^-_{3(aq)}.$ 

If the solubility product constant $K_{sp}$ of $AgIO_3$ at a given temperature is $1. 0 \times 10^{-8},$ what is the mass of $AgIO_3$ contained in $100\, ml$ of its saturated saolution ?

  • A
    $1.0 \times 10^{-4}\, g$
  • B
    $28.3 \times 10^{-2}\, g$
  • ✓
    $2.83 \times 10^{-3}\, g$
  • D
    $1.0 \times 10^{-7}\, g$
✓

Answer

Correct option: C.
$2.83 \times 10^{-3}\, g$
c
The correct answer Is:

(c) $: \quad A g I O_{3} \rightleftharpoons A g^{+}+I O_{3}^{-}[S=$ Solubility $]$

$K_{s p}=S^{2}$

or, $S^{2}=1.0 \times 10^{-8}$ or, $S=1.0 \times 10^{-4} \mathrm{mol} / \mathrm{lit}$

$=1.0 \times 10^{-4} \times 283 \quad \mathrm{g} / \mathrm{lit}$

$=\frac{1.0 \times 10^{-4} \times 283}{1000} \mathrm{gm} / \mathrm{ml}$

$=\frac{1.0 \times 10^{-4} \times 283 \times 100}{1000} \mathrm{gm} / 100 \mathrm{ml}$

$=28.3 \times 10^{-4} \mathrm{gm} / 100 \mathrm{ml}$

$=2.83 \times 10^{-3} \mathrm{gm} / 100 \mathrm{ml}$

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