In a screw gauge, $5$ complete rotations of the screw cause it to move a linear distance of $0.25\, cm$. There are $100$ circular scale divisions. The thickness of a wire measured by this screw gauge gives a reading of $4$ main scale divisions and $30$ circular scale divisions . Assuming negligible zero error, the thickness of the wire is
  • A$0.0430\,cm$
  • B$0.3150\,cm$
  • C$0.43 00\,cm$
  • D$0.2150\, cm$
JEE MAIN 2018, Medium
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