MCQ
In a $\triangle \text{ABC},$ if $\angle \text{A}-\angle \text{B}=33^\circ$ and $\angle \text{B}-\angle \text{C}=10^\circ,$ then $\angle \text{B} =$
  • A
    $35^\circ$
  • B
    $45^\circ$
  • C
    $55^\circ$
  • $25^\circ$

Answer

Correct option: D.
$25^\circ$
$\angle \text{A}-\angle \text{B}=33^\circ$ and $\angle \text{B}-\angle \text{C}=18^\circ$
$\Rightarrow \angle \text{A}=\angle \text{B}+33^\circ$ and $\angle \text{C}=\angle \text{B}-18^\circ$
Now, $\angle \text{A}+\angle \text{B}+\angle \text{C}=180^\circ$ [Angle sum property of triangle]
$\Rightarrow \angle \text{B}+33^\circ+\angle \text{B}+\angle \text{B}-18^\circ=180^\circ$
$\Rightarrow 3\angle \text{B}+15^\circ=180^\circ$
$\Rightarrow 3\angle \text{B}=165^\circ$
$\Rightarrow \angle \text{B}=55^\circ$
Hence, the correct answer is option $(d).$

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