Question
In a $\triangle\text{ABC},$ if $\angle\text{A}=55^\circ,\angle\text{B}=40^\circ,$ find $\angle\text{C}.$
✓
Answer
Given Data:
$\angle\text{B}=55^\circ,\angle\text{B}=40^\circ,$ then $\angle\text{C}=?$
We know that
In a $\triangle\text{ABC}$ sum of all angles of a triangle is 180°
i.e., $\angle\text{A}+\angle\text{B}+\angle\text{C}=180^\circ$
$\Rightarrow55^\circ+40^\circ+\angle\text{C}=180^\circ$
$\Rightarrow95^\circ+\angle\text{C}=180^\circ$
$\Rightarrow\angle\text{C}=180^\circ-95^\circ$
$\Rightarrow\angle\text{C}=85^\circ$
$\angle\text{B}=55^\circ,\angle\text{B}=40^\circ,$ then $\angle\text{C}=?$
We know that
In a $\triangle\text{ABC}$ sum of all angles of a triangle is 180°
i.e., $\angle\text{A}+\angle\text{B}+\angle\text{C}=180^\circ$
$\Rightarrow55^\circ+40^\circ+\angle\text{C}=180^\circ$
$\Rightarrow95^\circ+\angle\text{C}=180^\circ$
$\Rightarrow\angle\text{C}=180^\circ-95^\circ$
$\Rightarrow\angle\text{C}=85^\circ$
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