MCQ
In a $\triangle\text{ABC},$ side $BC$ is produced to $D$. If $\angle\text{ABC}=50^\circ$ and $\angle\text{ACD}=110^\circ$ then $\angle\text{A}=?$
- A$160^\circ$
- ✓$60^\circ$
- C$80^\circ$
- D$30^\circ$
✓
Answer
Correct option: B.
$60^\circ$
$\angle\text{ACD}=\angle\text{B}+\angle\text{A}\ ($Exterior angle property$)$
$\Rightarrow110^\circ=50^\circ+\angle\text{A}$
$\Rightarrow\angle\text{A}=60^\circ$
$\Rightarrow110^\circ=50^\circ+\angle\text{A}$
$\Rightarrow\angle\text{A}=60^\circ$
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