MCQ
In a $U-$ tube, the liquid level stands at same level when it is at rest. When $U-$ tube is accelerated towards right, as shown in figure, the difference $h$ between level of two arms will be


- A$\frac {aL}{2g}$
- B$\frac {gL}{2a}$
- C$\frac {gL}{a}$
- ✓$\frac {aL}{g}$




