MCQ
In ammonium-phosphomolybdate, the oxidation state of Mo is ${ }^{+}$ $..........$.
- A$8$
- B$4$
- C$10$
- D$6$
Let $X =$ oxidation state of $Mo$ in $MoO _3$
$X +(-2) \times 3=0$
$X =+6$
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takes places through the mechanism given below :
$NO + Br _2 \Leftrightarrow NOBr _2 \text { (fast) }$
$NOBr _2+ NO \rightarrow 2 NOBr \text { (slow) }$
The overall order of the reaction is $.....$.
The products formed in the above reaction are
$CH_3-CH_2-CHO \, + $ (image) $\xrightarrow[{0 - 5{}^ \circ C}]{{O\mathop H\limits^ \ominus }} \, ?$