Download App

Sets — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsSets1 Mark
MCQ
In an examination $70\%$ students passed both in Mathematics and Physics $85\%$ passed in Mathematics and $80\%$ passed in Physics If $30$ students have failed in both the subjects then the total number of students who appeared in the examination is equal to:
  • A
    $900$
  • ✓
    $600$
  • C
    $150$
  • D
    $100$
✓

Answer

Correct option: B.
$600$
Student passed in atleast one subject
$= \ce{n (P ∪ M) = n(P) + n(M) -n (P ∪ M)}$
$= 80 + 85 - 70$
$= 95$
$\therefore 5\%$ student failed in both the subjects
$\Rightarrow 5\%$ of total students $= 30$
$\Rightarrow$ Total students $=\frac{30\times100}{5}=600$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Sets→Sets — all question types→Maths STD 11 Science question papers→CBSE Board STD 11 Science question papers→CBSE Board question paper generator→

Similar questions

The sum of the series $1^2 + 3^2 + 5^2 + ...$ to $n$ terms is:
→
Among $14$ players, $5$ are bowlers. In how many ways a team of $11$ may be formed with at least $4$ bowlers?
→
${\sin ^4}\frac{\pi }{8} + {\sin ^4}\frac{{3\pi }}{8} + {\sin ^4}\frac{{5\pi }}{8} + {\sin ^4}\frac{{7\pi }}{8} = $
→
If $|2\text{x} – 3|<|\text{x} + 5|,$ then $x$ belongs to:
→
Let $A B C$ be a triangle and $M$ be a point on side $A C$ closer to vertex $C$ than $A$. Let $N$ be a point on side $A B$ such that $M N$ is parallel to $B C$ and let $P$ be a point on side $B C$ such that $M P$ is parallel to $A B$. If the area of the quadrilateral $B N M P$ is equal to $\frac{5}{18}$ of the area of $\triangle A B C$, then the ratio $A M / M C$ equals
→
If $\omega$ is complex cube root of unity whose imaginary part is positive $\&$ $|z -w| = |z + w|,$ then $arg(z)$ can be-
→
The locus of the point of intersection of the lines $bxt - ayt = ab$ and $bx + ay = abt$ is
→
The points $C$ and $D$ on a semicircle with $A B$ as diameter are such that $A C=1, C D=2$ and $D B=3$. Then, the length of $A B$ lies in the interval.
→
$A = (1, -1, 2)$ and $B = (2, 3, 7)$ are two points. lf $P, O$ divide $AB$ in the ratios $2 : 3, -2 : 3$ respectively then $P_x + Q_y​=$
→
A straight line through the vertex $P$ of a triangle $P Q R$ intersects the side $Q R$ at the point $S$ and the circumcircle of the triangle $P Q R$ at the point $T$. If $S$ is not the centre of the circumcircle, then

$(A)$ $\frac{1}{\mathrm{PS}}+\frac{1}{\mathrm{ST}}<\frac{2}{\sqrt{\mathrm{QS} \times \mathrm{SR}}}$

$(B)$ $\frac{1}{\mathrm{PS}}+\frac{1}{\mathrm{ST}}>\frac{2}{\sqrt{\mathrm{QS} \times \mathrm{SR}}}$

$(C)$ $\frac{1}{\mathrm{PS}}+\frac{1}{\mathrm{ST}}<\frac{4}{\mathrm{QR}}$

$(D)$ $\frac{1}{\mathrm{PS}}+\frac{1}{\mathrm{ST}}>\frac{4}{\mathrm{QR}}$

→