$n = \frac{p}{{2l}}\sqrt {\frac{T}{m}} $
==> $\frac{{{n_2}}}{{{n_1}}} = \frac{{{l_1}}}{{{l_2}}} \Rightarrow {n_2} = \frac{{25}}{{16}} \times 256 = 400\,\,\,Hz$

${y}=1.0\, {mm} \cos \left(1.57 \,{cm}^{-1}\right) {x} \sin \left(78.5\, {s}^{-1}\right) {t}$
The node closest to the origin in the region ${x}>0$ will be at ${x}=\ldots \ldots \ldots\, {cm}$
$Y = A\sin (100t)\cos (0.01x)$
where $Y$ and $A$ are in millimetre, $t$ is in seconds and $x$ is in metre. The velocity of wave is ..... $m/s$