d
$: \rightarrow$ Isobaric expansion of Ideal gas
$\therefore$ Pressure $=P=$ constant
volume is increased.
Work Done can not be jero, because volume is increased, hence $\Delta V > 0$
$W D=P \Delta V$
$W D > 0$
From, $P V=n R T$
$V \propto T$
As volume increased, Temperature also increased
So $\Delta u \neq 0$
From, first law of thermodynamics
$\Delta \theta=\Delta U+W D$
$\Delta \theta \neq 0$
Now, $V=\frac{n R}{p} T$
Differentiate both sides w.r.t. $T$
$\frac{d V}{d T}=\frac{n R}{P} \frac{d T}{d T}$
$\frac{d v}{d T}=\underbrace{\frac{n R}{P}} & \longrightarrow \text { constant }(\because \text { Isobaric) }$
Differentiate again w.r.l. $T$
$\frac{d^2 V}{d T^2}=0$