MCQ
In an isosceles triangle $ABC$ if $AC = BC$ and $AB^2 = 2AC^2$, then $\angle\text{C}=$
  • A
    $30^\circ$
  • B
    $45^\circ$
  • $90^\circ$
  • D
    $60^\circ$

Answer

Correct option: C.
$90^\circ$
In isosceles $\triangle\text{ABC},\ \text{AC}=\text{BC}$



and $AB^2 = AC^2 + AC^2 = 2AC^2$
$= AC^2 + BC^2 (AC = BC)$
By converse of Pythagoras Theorem,
$\angle\text{C}=90^\circ$

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