In an $LCR $ circuit as shown below both switches are open initially. Now switch $S_1$ is closed, $S_2$ kept open. ( $q$ is charge on the capacitor and $\tau = RC$ is Capacitive time constant). Which of the following statement is correct?
AAt $t=\frac{\tau}{2}$,$q=C V$ $(1-e^{-1})$
B
Work done by the battery is half of the energy dissipated in the resistor
CAt $t=$$\;\tau $ ,$q= $ $\frac{{{\rm{CV}}}}{2}$
DAt $t= $${2 \tau }$ ,$q=CV$ $(1-e^{-2})$
JEE MAIN 2013, Medium
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DAt $t= $${2 \tau }$ ,$q=CV$ $(1-e^{-2})$
d Charge on he capacitor at any time $t$ is given by
$q=C V\left(1-e^{t / \tau}\right)$
at $t=2 \tau$
$q=C V\left(1-e^{-2}\right)$
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