MCQ
In any triangle ABC, the simplified form of `$(cos2A)/a^2 - (cos2B)/b^2$` is ______
  • A
    $a^2+b^2$
  • B
    $1 /\left(a^{\wedge} 2-b^{\wedge} 2\right)^{\circ}$
  • C
    $a^2-b^2$
  • $1 / a^{\wedge} 2-1 / b^{\wedge} 2^{\prime}$

Answer

Correct option: D.
$1 / a^{\wedge} 2-1 / b^{\wedge} 2^{\prime}$
D

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