MCQ
In any $\triangle\text{ABC},2(\text{bc}\cos\text{A + ca}\cos\text{B + ab}\cos\text{C})=$
  • A
    $\text{abc}$
  • B
    $\text{a + b + c}$
  • $\text{a}^2+\text{b}^2+\text{c}^2$
  • D
    $\frac{1}{\text{a}^2}+\frac{1}{\text{b}^2}+\frac{1}{\text{c}^2}$

Answer

Correct option: C.
$\text{a}^2+\text{b}^2+\text{c}^2$
Using cosine rule, we have$2(\text{bc}\cos\text{A}+\text{ca}\cos\text{B}+\text{ab}\cos\text{C})$
$=2\text{bc}\Big(\frac{\text{b}^2+\text{c}^2-\text{a}^2}{2\text{bc}}\Big)+2\text{ca}\Big(\frac{\text{c}^2+\text{a}^2-\text{b}^2}{2\text{ca}}\Big)+2\text{ab}\Big(\frac{\text{a}^2+\text{b}^2-\text{c}^2}{2\text{ab}}\Big)$
$=\text{b}^2+\text{c}^2-\text{a}^2+\text{c}^2+\text{a}^2-\text{b}^2+\text{a}^2+\text{b}^2-\text{c}^2$
$=\text{a}^2+\text{b}^2+\text{c}^2$
Hence, the correct answer is option (c).

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If ${1 \over 2} \le {\log _{0.1}}x \le 2$ then
If x = 5 and y = - 2, then x - 2y = 9. The contrapositive of this proposition is.
If $(1 + i)(1 + 2i)(1 + 3i).....(1 + ni) = a + ib$, then $2.5.10....$$(1 + {n^2})$ is equal to
If $a,\;b,\;c,\;d,\;e$ are prime integers, then the number of divisors of $a{b^2}{c^2}de$ excluding $1$ as a factor, is
A point $P$ moves in such a way that the ratio of its distance from two coplanar points is always a fixed number $( \ne 1)$. Then its locus is
In the expansion of ${(1 + x)^n}$ the sum of coefficients of odd powers of $x$ is
Let $z_k=\cos \left(\frac{2 k \pi}{10}\right)+ i \sin \left(\frac{2 k \pi}{10}\right) ; k =1,2, \ldots 9$.

List $I$ List $II$
$P.$ For each $z_k$ there exists a $z_j$ such that $z_k \cdot z_j=1$ $1.$ True
$Q.$ There exists a $k \in\{1,2, \ldots ., 9\}$ such that $z_{1 .} . z=z_k$ has no solution $z$ in the set of complex numbers. $2.$ False
$R.$ $\frac{\left|1-z_1\right|\left|1-z_2\right| \ldots . .\left|1-z_9\right|}{10}$ equals $3.$ $1$
$S.$ $1-\sum_{k=1}^9 \cos \left(\frac{2 k \pi}{10}\right)$ equals $4.$ $2$

Codes: $ \quad P \quad Q \quad R \quad S$

On the ellipse $\frac{x^{2}}{8}+\frac{y^{2}}{4}=1$ let $P$ be a point in the second quadrant such that the tangent at $\mathrm{P}$ to the ellipse is perpendicular to the line $x+2 y=0$. Let $S$ and $\mathrm{S}^{\prime}$ be the foci of the ellipse and $\mathrm{e}$ be its eccentricity. If $\mathrm{A}$ is the area of the triangle $SPS'$ then, the value of $\left(5-\mathrm{e}^{2}\right) . \mathrm{A}$ is :
The radius of the circle ${x^2} + {y^2} + 4x + 6y + 13 = 0$ is
The length of the chord of the parabola $y^2 = x $ which is bisected at the point $ (2, 1)$  is