MCQ
In Bainbridge mass spectrograph a potential difference of $1000 V$ is applied between two plates distant $1$ cm apart and magnetic field in $B = 1T$. The velocity of undeflected positive ions in m/s from the velocity selector is
  • A
    ${10^7}m/s$
  • B
    ${10^4}m/s$
  • ${10^5}m/s$
  • D
    ${10^2}m/s$

Answer

Correct option: C.
${10^5}m/s$
c
(c) $v = \frac{E}{B}$; where $E = \frac{V}{d} = \frac{{1000}}{{1 \times {{10}^{ - 2}}}} = {10^5}\,V/m$

==> $v = \frac{{{{10}^5}}}{1} = {10^5}m/s$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free