(Rounded-off to the nearest integer)
- A$170$
- ✓$173$
- C$181$
- D$141$
(Rounded-off to the nearest integer)
$0.154 \times 3 \times v =0.25 \times 40 \times 8$
$v =173.16=173 \,ml$
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$(A)$ and $(B)$ are
${N_2}{H_4}\left( l \right) + 2{H_2}{O_2}\left( l \right) \to \mathop {{N_2}\left( g \right) + 4{H_2}O\left( l \right);}\limits_{{\Delta_r} H_1^o = - 818\,kJ/mol} $
${N_2}{H_4}\left( l \right) + {O_2}\left( g \right) \to \mathop {{N_2}\left( g \right) + 2{H_2}O\left( l \right);}\limits_{{\Delta _r}H_2^o = - 622\,kJ/mol} $
${H_2}\left( g \right) + \frac{1}{2}{O_2}\left( g \right) \to \mathop {{H_2}O\left( l \right);}\limits_{{\Delta _r}H_3^o = - 285\,kJ/mol} $
.......$kJ/mol$

$(I)$ Number of $S-S$ bonds in $H_2S_nO_6$ are $(n + 1)$
$(II)$ When $F_2$ reacts with water gives $HF, O_2$ and $O_3$
$(III)$ $LiNO_3$ and $BaCl_2$ compounds are used in fire works
$(IV)$ $Be$ and $Mg$ hydrides are ionic and polymeric