(Rounded-off to the nearest integer)
(Rounded-off to the nearest integer)
$0.154 \times 3 \times v =0.25 \times 40 \times 8$
$v =173.16=173 \,ml$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Consider the above reaction. The percentage yield of amide product is ...... . (Round off to the Nearest Integer). (Given : Atomic mass : $C : 12.0\, u , H : 1.0 \,u,N : 14.0\, u , O : 16.0\, u , Cl : 35.5\, u )$


$\mathrm{Zn}(\mathrm{s})+\mathrm{Cu}^{2+}(0.02 \mathrm{M}) \rightarrow \mathrm{Zn}^{2+}(0.04 \mathrm{M})+\mathrm{Cu}(\mathrm{s})$
$\mathrm{E}_{\text {cell }}=...... \,\times 10^{-2} \,\mathrm{~V} { (Nearest integer) }$
${\left[\text { Use }: \mathrm{E}_{\mathrm{Cu} / \mathrm{Cu}^{2+}}^{0}=-0.34\, \mathrm{~V}, \mathrm{E}_{2 \mathrm{n} / \mathrm{Zn}^{2+}}^{0}=+0.76 \,\mathrm{~V}\right.}$
$\left.\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059\, \mathrm{~V}\right]$
Total number of optically active isomers shown by $\mathrm{C}_4 \mathrm{H}_8 \mathrm{Cl}_2$, obtained in the above reaction is......................