MCQ
In Bohr’s model of atom when an electron jumps from $n =1$ to $n=3,$ how much energy will be absorbed
- A$2.15 \times 10^{-10} \, ergs$
- ✓$0.1911 \times 10^{-10} \, ergs$
- C$2.389 \times 10^{-10} \, ergs$
- D$0.239 \times 10^{-10} \, ergs$
$E_{1}=-\frac{1312}{(1)^{2}}=-1312 \mathrm{kJ} \mathrm{mol}^{-1}$
Similarly energy when $n=3,\left(E_{3}\right)$
$=-\frac{1312}{(3)^{2}}$
$=-145.7 \mathrm{kJ} \mathrm{mol}^{-1}$
The energy absorbed when an electron jumps from $n=1$ to $n=3$
$E_{3}-E_{1}=-145.7-(-1312)=1166.3 \mathrm{kJ} \mathrm{mol}^{-1}$
$=\frac{1166.3}{6.023 \times 10^{23}}=193.6 \times 10^{-23} \mathrm{kJ}$
$=193.6 \times 10^{-20} \mathrm{J}\left[1\right.$ Joule $\left.=10^{7} \mathrm{ergs}\right]$
$\Rightarrow 193.6 \times 10^{-13}$ ergs $=0.1936 \times 10^{-10} \mathrm{ergs}$
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