MCQ
In carbon monoxide molecules, the carbon and the oxygen atoms are separated by distance $1.2 \,\mathring A$. The distance of the centre of mass, from the carbon atom is ........ $\mathring A$
- A$0.48$
- B$0.51$
- C$0.56$
- ✓$0.69$
mass of the $C$ atom $=12$ units
mass of the $O$ atom $=16$ units
Position of the $C$ atom is taken to be origin.
position of the centre of mass :
$=\frac{1.2 \times 16}{12+16}=\frac{1.2 \times 16}{28}=0.69 \mathring A$
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