MCQ
In case of osmosis solvent molecules move from
- ✓Higher vapour pressure to lower vapour pressure
- BHigher concentration to lower concentration
- CLower vapour pressure to higher vapour pressure
- DHigher osmotic pressure to lower osmotic pressure
✓
Answer
Correct option: A.
Higher vapour pressure to lower vapour pressure
a
Osmosis is defined as the spontaneous flow of solvent molecules through semipermeable membrane from a pure solvent to a solution or from a dilute to a concentrated solution. If two solutions of unequal concentrations are separated by a semipermeable membrane, the solvent molecules from a solution of lower concentration move towards a solution of higher concentration.
Osmosis is defined as the spontaneous flow of solvent molecules through semipermeable membrane from a pure solvent to a solution or from a dilute to a concentrated solution. If two solutions of unequal concentrations are separated by a semipermeable membrane, the solvent molecules from a solution of lower concentration move towards a solution of higher concentration.
And according to vapour pressure theory; a solvent can pass through a semipermeable membrane because the vapour pressure of the pure solvent is higher than the vapour pressure of the solution and as the solvent moves toward solution,
Thus, higher vapour pressure to lower vapour pressure is the correct answer.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
વિધાન : Ozone is powerful oxidising agent in comparison to $O_2$.
કારણ : Ozone is diamagnetic but $O_2$ is paramagnetic.
→કારણ : Ozone is diamagnetic but $O_2$ is paramagnetic.
The $IUPAC$ name of $\begin{matrix}
C{{H}_{3}}-CH-C-C-NH \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,| \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}\,\,\,\,O\,\,\,\,\,\,\,O\,\,\,\,\,\,Br \\
\end{matrix}$ is
→C{{H}_{3}}-CH-C-C-NH \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,| \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}\,\,\,\,O\,\,\,\,\,\,\,O\,\,\,\,\,\,Br \\
\end{matrix}$ is
Product $(A)$ and $(B)$ respectively are :-
→Consider a titration of potassium dichromate solution with acidified Mohr's salt solution using diphenylamine as indicator. The number of moles of Mohr's salt required per mole of dichromate is
The mixture of concentrated $HCl$ and $HN{O_3}$ made in $3 : 1$ ratio contains
→Heating of ammonium dichromate produces
Why does the conductivity of a solution decreases with dilution because :
Given
→$(i)\,\,C\,({\rm{graphite}})\, + \,{O_2}{\kern 1pt} (g)\, \to \,C{O_2}\,(g);\,\Delta r{H^\circleddash} = x\,\,kJ\,mo{l^{ - 1}}$
$(ii)\,\,C\,({\rm{graphite}})\, + \,\frac{1}{2}{O_2}{\kern 1pt} (g)\, \to \,CO\,(g);\,\Delta r{H^\circleddash} = y\,\,kJ\,mo{l^{ - 1}}$
$(iii)\,\,CO\,(g)\, + \,\frac{1}{2}{O_2}{\kern 1pt} (g)\, \to \,C{O_2}\,(g);\,\Delta r{H^\circleddash} = z\,\,kJ\,mo{l^{ - 1}}$
Based on the above thermochemical equations, find out which one of the following algebraic relationships is correct?
The following sets of quantum numbers represent four electrons in an atom
→$(i)$ $n\, = 4, l\, = 1$ $(ii)$ $n\, = 4, l\, = 0$
$(iii)$ $n\, = 3, l\, = 2$ $(iv)$ $n\, = 3, l\, = 1$
The sequence representing increasing order of energy, is
$X\xrightarrow{{C{l_2}}}$ Benzotrichloride $\xrightarrow{{Hydrolysis}}Y$
→$X$ and $Y$ respectively are :