MCQ
In $C{H_3}C{H_2}Br,\,\,$$\% $ of $Br$ is
- A$80$
- ✓$75$
- C$70$
- D$7$
✓
Answer
Correct option: B.
$75$
b
(b) $\%$ of $Br$ $ = \frac{{{\rm{Mass}}\,\,{\rm{of}}\,\,Br}}{{{\rm{Mass of organic compound}}}} \times 100$
(b) $\%$ of $Br$ $ = \frac{{{\rm{Mass}}\,\,{\rm{of}}\,\,Br}}{{{\rm{Mass of organic compound}}}} \times 100$
$ = \frac{{80}}{{109}} \times 100 = 73.39\,\% $ or approx. $ 75$ $\%$
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