MCQ
In $CuS{O_4}$ solution when electric current equal to $2.5$ faraday is passed, the gm equivalent deposited on the cathode is
- A$1$
- B$1.5$
- C$2$
- ✓$2.5$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| column $I$ | column $II$ |
| $(A)$ $CO _2( s ) \rightarrow CO _2( g )$ | $(p)$ phase transition |
| $(B)$ $CaCO _3( s ) \rightarrow CaO$ (s) $+ CO _2( g )$ | $(q)$ allotropic change |
| $(C)$ $2 H \bullet \rightarrow H _2( g )$ | $(r)$ $\Delta H$ is positive |
| $(D)$ $P_{\text {(white, solid) }} \rightarrow P_{\text {(red, solid) }}$ | $(s)$ $\Delta S$ is positive |
| $(t)$ $\Delta S$ is negative |
$\mathrm{Sn}^{4+}, \mathrm{Sn}^{2+}, \mathrm{Pb}^{2+}, \mathrm{Tl}^{3+}, \mathrm{Pb}^{4+}, \mathrm{Tl}^{+}$