Question
In cyclic quadrilateral ABCD $m\angle A=100^{\circ}$, then find $m\angle C$.
✓
Answer
Opposite angles of a cyclic quadrilateral are supplementary.
$m\angle A + m\angle C = 180^{\circ}$
$100^{\circ} + m\angle C = 180^{\circ}$
$m\angle C = 180^{\circ} - 100^{\circ} = 80^{\circ}$
$m\angle A + m\angle C = 180^{\circ}$
$100^{\circ} + m\angle C = 180^{\circ}$
$m\angle C = 180^{\circ} - 100^{\circ} = 80^{\circ}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
See fig, In ∆ ABC, seg AD ⊥ seg BC, ∠C = 45°, BD = 5 and AC = 8√2 then find AD and BC.
Ratio of corresponding sides of two similar triangles is 4:7 then find the ratio of their areas = ?
Find the value of following determinant:
$\left|\begin{array}{cc}\frac{1}{2} & \frac{-2}{3} \\ \frac{3}{4} & \frac{-4}{5}\end{array}\right|$
→$\left|\begin{array}{cc}\frac{1}{2} & \frac{-2}{3} \\ \frac{3}{4} & \frac{-4}{5}\end{array}\right|$
Without actual division, show that the following rational numbers is a non-terminating repeating decimal:$\frac{9}{35}$
→The length of a rectangular field is $23\ m$ more than its breadth. If the perimeter of the field is $206\ m,$ then its area is:
→$\frac{1-\tan ^2 45^{\circ}}{1+\tan ^2 45^{\circ}}=?$
→Are triangles in figure similar ? If yes then write the test of similarity.
The following are quadratic equations in x?
$\text{2x}^2+\frac{5}{2}\text{x}-\sqrt{3}=0$
→$\text{2x}^2+\frac{5}{2}\text{x}-\sqrt{3}=0$
In fig 2.13, ∠ PQR = 90°,seg QN ⊥ seg PR, PN = 9, NR = 16. Find QN.
$(x-1)^2=2 x+3$
→