Question
In each of the verify that the given function (explicit or implicit) is a solution of the corresponding differential equation:
$\text{y} = \text{Ax} \ :\ \text{xy}' = \text{y} (\text{x} \neq0)$

Answer

Given: y = Ax .....(i)
To prove: y given by eq. (i) is a solution of differential equation $\text{xy}' = \text{y}(\text{x} \neq0)\ ....(\text{ii})$
Proof: From eq. (i) y' = A(1) = A
L.H.S. of eq. (ii) = xy' = xA = Ax = y = R.H.S. of eq. (ii)
$\therefore$ y given by eq. (i) is a solution of differential equation $\text{xy}' = \text{y}(\text{x} \neq 0).$

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