MCQ
In electrolysis of dilute ${H_2}S{O_4}$using platinum electrodes
- ✓${H_2}$ is evolved at cathode
- B$N{H_3}$ is produced at anode
- C$C{l_2}$ is obtained at cathode
- D${O_2}$ is produced
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$\frac{1}{2}{P_4}(s) + 3C{l_2}(g) \to 2PC{l_3}(l)\,;$ $\Delta H=-635 \,kJ$
$PC{l_3}(l) + C{l_2}(g) \to PC{l_5}(s)\,;$ $\Delta H=-137\, kJ$
The value of heat of formation of $PCl_5$ is ......$kJ\,mol^{-1}$