MCQ
In Fig. $AD = 4\ cm, BD = 3\ cm$ and $CB = 12\ cm,$ find the $\cot\theta.$
  • $​​\frac{12}{5}$
  • B
    $​​\frac{5}{12}​​ $
  • C
    $​​\frac{13}{12}$
  • D
    $​​\frac{12}{13}$

Answer

Correct option: A.
$​​\frac{12}{5}$
We have the following given data in the figure, $AD= 4\ cm, BD = 3\ cm, CB = 12\ cm$
Now we will use Pythagoras theorem in $\triangle\text{ABD},$
$\text{AB}=\sqrt{3^2+4^2}$
$=5\text{ cm}$
Therefore,
$\cot\theta=\frac{\text{CB}}{\text{AB}}$
$=\frac{12}{5}$
So the answer is $(a)$

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