MCQ
In Fig. AOB is a straight line such that $\angle \text{AOC}=(3\text{x}+10)^\circ. \angle \text{COD}=50^\circ$ and $\angle \text{BOD}=(\text{x}-8)^\circ.$ The value of $x$ is:
- ✓$32$
- B$36$
- C$42$
- D$52$
✓
Answer
Correct option: A.
$32$
$\angle \text{AOC}+\angle \text{COD}+\angle \text{BOD}=180^\circ [\text{AOB}$ is a straight line$]$
$\Rightarrow (3\text{x}+10)^\circ+50^\circ+(\text{x}-8)^\circ=180^\circ$
$\Rightarrow 3\text{x}+10+50+\text{x}-8=180$
$\Rightarrow 4\text{x}+52=180$
$\Rightarrow 4\text{x}=128$
$\Rightarrow \text{x}=32$
Hence, the correct answer is option $(a).$
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