MCQ
- A$43^{\circ}$
- B$30^{\circ}$
- ✓$34^{\circ}$
- D$40^{\circ}$
✓
Answer
Correct option: C.
$34^{\circ}$
(c) $34^{\circ}$
Since ABCD is a cyclic quadrilateral.
$\begin{array}{ll}\therefore & \angle A+\angle C=180^{\circ} \\
\Rightarrow & 2 x+40^{\circ}+4 x-64^{\circ}=180^{\circ} \\
\Rightarrow & 6 x=204^{\circ} \Rightarrow x=34^{\circ}\end{array}$
Since ABCD is a cyclic quadrilateral.
$\begin{array}{ll}\therefore & \angle A+\angle C=180^{\circ} \\
\Rightarrow & 2 x+40^{\circ}+4 x-64^{\circ}=180^{\circ} \\
\Rightarrow & 6 x=204^{\circ} \Rightarrow x=34^{\circ}\end{array}$
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