Question
In fig., if $AC = BD,$ then prove that $AB = CD$

Answer

$AC = BD . . . . [$Given$] . . . (1)$
$AC = AB + BC . . . . [$Point $B$ lies between $A$ and $C] . . . . (2)$
$BD = BC + CD . . . . [$Point $C$ lies between $B$ and $D] . . . . (3)$
Substituting $(2)$ and $(3)$ in $(1),$ we get
$AB + BC = BC + CD$
$\Rightarrow AB = CD . . . . [$Subtracting equals from equals$]$

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