In Fig. if A O B=125^ , then C O D is equal to - Vidyadip

MCQ

In Fig. if $\angle A O B=125^{\circ}$, then $\angle C O D$ is equal to

A
$45^{\circ}$
B
$65^{\circ}$
✓
$55^{\circ}$
D
$621 / 2^{\circ}$

✓

Answer

Correct option: C.

$55^{\circ}$

(c)$55^{\circ}$
We find that the circle touches the sides of quadrilateral $A B C D$. Therefore,
$\angle A O B+\angle C O D=180^{\circ} \qquad$ [See result at S.No. 22 at page 8.2 ]
$\Rightarrow \quad 125^{\circ}+\angle C O D=180^{\circ} \Rightarrow \angle C O D=55^{\circ}$

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