MCQ
In Fig. if $AOC$ is a straight line, then $x =$ 
- A$42^\circ $
- ✓$52^\circ$
- C$142^\circ $
- D$38^\circ$
$\angle \text{AOD}+\angle \text{DOB}+\angle \text{BOC}=180^\circ [ \because AOC$ is a straight line$]$
$\Rightarrow 38^\circ+\text{x}+90^\circ=180^\circ$
$\Rightarrow \text{x}+128^\circ=180^\circ$
$\Rightarrow \text{x}=52^\circ$
Hence, the correct answer is option $(b).$
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