MCQ
In Fig. if $\text{AB} || \text{CD}$, $\angle\text{ APQ} = 50^\circ$ and $\angle\text{PRD} = 130^\circ$, then $\angle\text{QPR}$ is:
  • A
    $130^\circ $
  • B
    $50^\circ$
  • $80^\circ$
  • D
    $30^\circ$

Answer

Correct option: C.
$80^\circ$
Since, $AB$ and $CD$ are parallel and $PR$ is a transversal.
$\therefore\angle\text{BPR}+\angle\text{PRD}=180^\circ[\therefore$ Sum of consecutive interior angle is $180^\circ ]$

$\Rightarrow \angle \text{BPR} +130^\circ=180^\circ$
$[\therefore\angle\text{PRD}=130^\circ]$
$\Rightarrow\angle \text{BPR}=180^\circ-130^\circ$
$\Rightarrow \angle \text{BPR}=50^\circ$
Also, $\angle\text{APQ}+\angle \text{QPR}+\angle\text{BPR}=180^\circ$
$[\therefore$ sum of all the angies on a straight line is $180^\circ ]$
$\Rightarrow 50^\circ+\angle\text{QPR}+50^\circ=180^\circ$
$\Rightarrow\angle\text{QPR}+100^\circ=180^\circ$
$\Rightarrow\angle \text{QPR}=180^\circ-100^\circ$
$\therefore\angle\text{QPR}=80^\circ$

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