MCQ
In Fig. $PO || RS$ and $\angle \text{PAB}=60^\circ$ and $\angle \text{ACS}=100^\circ.$ Then, $\angle \text{BAC}=$ 
- ✓$40$
- B$60$
- C$80$
- D$50$
Since, $PQ || RS$
$\therefore \angle \text{PAC}= \angle \text{ACS}=100^\circ$ [Corresponding angles]
Now, $\angle \text{PAC}=100^\circ$
$\Rightarrow \angle \text{PAB}+\angle \text{BAC}=100^\circ$
$\Rightarrow 60^\circ+\angle \text{BAC}=100^\circ$
$\Rightarrow \angle \text{BAC}=40^\circ$
Hence, the correct answer is option $(a).$
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