MCQ
In Fig. the quadrilateral $ABCD$ circumscribes a circle with centre $O$. If $\angle\text{AOB} = 115^\circ,$ then find $\angle\text{COD}.$
- A$23^\circ$
- B$24^\circ$
- C$127^\circ$
- ✓$115^\circ$
✓
Answer
Correct option: D.
$115^\circ$
$\therefore \angle\text{AOB} = \angle\text{COD}$ (vertically opposite angle)
$\therefore \angle\text{COD}=115^\circ$
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