MCQ
In Fig. the value of $x$ is:


- A$20$
- ✓$30$
- C$40$
- D$25$

$\angle \text{TRS}+\angle \text{TRQ}=180^\circ$ [Linear angles]
$\Rightarrow 5\text{x}^\circ+\angle \text{TRQ}=180^\circ$
$\Rightarrow \angle \text{TEQ}=180^\circ-5\text{x}^\circ$
Now, $\angle \text{QTR}+\angle \text{TRQ}=\angle \text{PQT}$ [Exterior angle property of triangle]
$\Rightarrow 3\text{x}^\circ+180^\circ-5\text{x}^\circ=120^\circ$
$\Rightarrow 2\text{x}^\circ=60^\circ$
$\Rightarrow \text{x}=30$
Hence, the correct answer is option $(b).$
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