Question
In figure 3.80, if PQ = 6, QR = 10, PS = 8 find TS.
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Answer
Given: PQ = 6, QR = 10, PS = 8
PT × PS = PR × PQ
This property is known as theorem of chords intersecting outside the circle.
⇒ PR = PQ + RQ = 6 + 10 = 16
⇒ PT × 8 = 16 × 6
⇒ PT = 12
TS = PT – PS = 12 – 8 = 4
PT × PS = PR × PQ
This property is known as theorem of chords intersecting outside the circle.
⇒ PR = PQ + RQ = 6 + 10 = 16
⇒ PT × 8 = 16 × 6
⇒ PT = 12
TS = PT – PS = 12 – 8 = 4
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