MCQ
In figure, $AB = AC$ and $\angle\text{ACD} = 115^\circ.$ Find $\angle\text{A}?$
  • A
    $115^{\circ}$
  • $50^{\circ}$
  • C
    None of these
  • D
    $60^{\circ}$

Answer

Correct option: B.
$50^{\circ}$
$C =180^{\circ}-115^{\circ}=65^{\circ} AB = AC$ And hence $\angle B =\angle C =65^{\circ}$. Then $A =180^{\circ}-2 \times 65^{\circ}=50^{\circ}$

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