MCQ
In figure, $ABCD$ and $AEFG$ are both parallelograms if $\angle\text{C} = 80^\circ,$ then $\angle\text{DGF}$ is: 

- A$0^\circ$
- B$60^\circ$
- C$120^\circ$
- ✓$80^\circ$

As $\angle\text{A} = 80^\circ$ opposite angles of a parallelogram are equal and $\angle\text{DGF} = 80^\circ$ as $GF$ is parallel to $AB$, corresponding angles are equal.
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