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Geometry — MATHS STD 6 — Question

Gujarat BoardEnglish MediumSTD 6MATHSGeometry1 Mark
Question
In Figure:
$a.\ \angle\text{AOD}$ is a/ an $.....$ angle.
$b.\ \angle\text{COA}$ is a/ an $.....$ angle.
$c.\ \angle\text{AOE}$ is a/ an $.....$ angle.
✓

Answer

$a.\ \angle\text{AOD}$ is a/ an right angle.
$b.\ \angle\text{COA}$ is a/ an acute angle.
$c.\ \angle\text{AOE}$ is a/ an obtuse angle.
Solution:
$a.$ Since, $\angle\text{AOD}=\angle\text{AOB}+\angle\text{BOC}+\angle\text{COD}=30^\circ+20^\circ+40^\circ=90^\circ$
So, $\angle\text{AOD}=90^\circ$ is a right angle.
$b.$Since, $\angle\text{COA}=\angle\text{COB}+\angle\text{BOA}=20^\circ+30^\circ=50^\circ$ Because $\angle\text{COA}=50^\circ<90^\circ.$
So, $\angle\text{COA}$ is an acute angle.
$c.$Since, $\angle\text{AOE}=\angle\text{AOB}+\angle\text{BOC}+\angle\text{COD}+\angle\text{DOE},$
$=30^\circ+20^\circ+40^\circ+40^\circ=130^\circ$
Because $\angle\text{AOE}=130^\circ>90^\circ$ So, $\angle\text{AOE}$ is an obtuse angle.
 

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