Question
In Figure, common tangents AB and CD to two circles intersect at E. Prove that AB = CD.

Answer

Given common tangent AB and CD to two circles intersecting at E. To prove AB = CD
Proof: EA = EC ...(i) [the lengths of tangents drawn from an internal point to a circle are equal] EB = ED ...(ii) On adding Eqs. (i) and (ii), we get EA + EB = EC + ED ⇒ AB = CD Hence proved.

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