Question
In figure, find the area of $\triangle\text{GEF}.$
✓
Answer
Given:
Here we can see that rectangle ABCD and Parallelogram GEF are between the same base and same parallels. Hence, Area of Rectangle $\triangle\text{GEF}=\frac{1}{2}\text{Area of parallelogram ABCD}$$=\frac{1}{2}\times\text{AD}\times\text{CD}$
$=\frac{1}{2}\times8\times6$
$=24\text{cm}^2$
Hence we get the result as Area of $\triangle\text{GEF}=24\text{cm}^2$
- ABCD is a rectangle.
- CD = 6cm
- AD = 8cm
Here we can see that rectangle ABCD and Parallelogram GEF are between the same base and same parallels. Hence, Area of Rectangle $\triangle\text{GEF}=\frac{1}{2}\text{Area of parallelogram ABCD}$$=\frac{1}{2}\times\text{AD}\times\text{CD}$$=\frac{1}{2}\times8\times6$
$=24\text{cm}^2$
Hence we get the result as Area of $\triangle\text{GEF}=24\text{cm}^2$
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