MCQ
In Figure. if $AB | | CD$, then:


- A$\angle2=\angle3$
- B$\angle1=\angle4$
- C$\angle4=\angle1+\angle2$
- ✓$\angle1+\angle2=\angle3+\angle4$

Given, $AB | | CD$ and $AC$ is the transversal.
So, $\angle1=\angle3$
Also, in $\triangle\text{ABC},$ $\angle3+\angle4=\angle1+\angle2$
$[\because$ exterior angle = sum of two opposite interior angles$]$
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