MCQ
In figure, if $\angle\text{AOB}=125^\circ,$ then $\angle\text{COD}$ is equal to:
  • A
    62.5°
  • B
    45°
  • C
    35°
  • 55°

Answer

Correct option: D.
55°
we know that, the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle.i.e., $\angle\text{AOB}+\angle\text{COD}=180^\circ$
$\Rightarrow\ \angle\text{COD}=180^\circ-\angle\text{AOB}$
=180º - 125º = 55º

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