In figure, if $\angle\text{AOB}=125^\circ,$ then $\angle\text{COD}$ is equal to:
A
62.5°
B
45°
C
35°
✓
55°
✓
Answer
Correct option: D.
55°
we know that, the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle.i.e., $\angle\text{AOB}+\angle\text{COD}=180^\circ$
$\Rightarrow\ \angle\text{COD}=180^\circ-\angle\text{AOB}$
=180º - 125º = 55º
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