Question
In Figure. $QS \bot PR, RT \bot PQ$ and $QS = RT.$
  1. Is $\triangle\text{QSR}\cong\triangle\text{RTQ}?$ Give reasons.
  2. Is $\triangle\text{PQR}=\triangle\text{PRQ}?$ Giveb reasons.

Answer

  1. In $\triangle\text{QSR}$ and $\triangle\text{RTQ},$
$QS = RT [$given$]$
$\angle\text{QSR}=\angle\text{QTR}=90^{\circ}$
$\text{QR}=\text{QR}$ [common side]
By $RHS$ congruence criterion, $\triangle\text{QSR}\cong\triangle\text{RTQ}$
  1. Yes, $\triangle\text{PQR}=\triangle\text{PRQ}[$ by $CPCT]$

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