Question
In following case, find a and b.
$\big(\frac{\text{a}}{4}, \text{a}-2\text{b}\big)=(0, 6+\text{b})$

Answer

$\big(\frac{\text{a}}{4}, \text{a}-2\text{b}\big)=(0, 6+\text{b})$
$\Rightarrow \frac{\text{a}}{4}=0\Rightarrow\text{a}=0$
and $\text{a}-2\text{b}=6+\text{b}$
$\Rightarrow0-2\text{b}=6+\text{b}$
$\Rightarrow\text{b}=-2$
$\therefore \ \text{a}=0, \text{b}=-2$

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