MCQ
In Friedel Craft's alkylation, besides $AlC{l_3}$ the other reactants are
- ✓${C_6}{H_6} + C{H_3}Cl$
- B${C_6}{H_6} + C{H_4}$
- C${C_6}{H_6} + N{H_3}$
- D${C_6}{H_6} + C{H_3}COCl$

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$C{H_3} - C \equiv C - C{H_3}\xrightarrow{{{H_2}/Pd - BaS{O_4}}}$ $A\xrightarrow{{B{r_2}/CC{l_4}}}C$
$C{H_3} - C \equiv C - C{H_3}\xrightarrow{{Na/Liq.\,N{H_3}}}$ $B\xrightarrow{{B{r_2}/{H_2}O}}D$
(Use $R =8.31\, J\, K ^{-1}\, mol ^{-1} ; \log 2=0.3010$. In $10=$ $2.3, \log 3=0.477$ )

$2s$ $2{p_x}$ $2{p_y}$ $2{p_z}$
(at. mass $Ag =108; Br = 80$)