MCQ
In fructose, the possible optical isomers are
- A$12$
- ✓$8$
- C$16$
- D$4$
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$K = \left( {4.5 \times {{10}^{11}}{S^{ - 1}}} \right){e^{ - \left( {28000\frac{{{K^2}mol}}{J}} \right)\frac{R}{T}}}$
The activation energy of reaction (in $J/mol$) is
$\mathrm{A}+\mathrm{B} \rightarrow \mathrm{M}+\mathrm{N} \text { in } \mathrm{kJ} \mathrm{mol}^{-1}$ is equal to ...... . (Integer answer)
