Gujarat BoardEnglish MediumSTD 9MathsCircles2 Marks
Question
In given figure, $\angle A B C=69^{\circ}, \angle A C B=31^{\circ}$, find $\angle B D C$.
✓
Answer
From the given figure, in $\triangle A B C$, we can write
$\angle A B C+\angle A C B+\angle B A C=180^{\circ}(\text { by angle sum property })$
$69^{\circ}+31^{\circ}+\angle B A C=180^{\circ}$
$\Rightarrow \angle B A C=180^{\circ}-100^{\circ}=80^{\circ}$
$\angle B D C=\angle B A C \text { (Angles in the same segment) }$
$\therefore \angle B D C=80^{\circ}$
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