Question
In given $L - R$ circuit



$I=\frac{\varepsilon}{2 R}$
$\mathrm{IR}=\frac{\varepsilon}{2}$
So $\frac{\mathrm{LdI}}{\mathrm{dt}}=\frac{\varepsilon}{2}$
$\frac{\mathrm{d} \mathrm{I}}{\mathrm{dt}}=\frac{\varepsilon}{2 \mathrm{L}}$
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